When an electric current is passed through a solenoid,how can we determine which end behaves as a North pole and which as a South pole? Explain.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) When an electric current flows through a solenoid (coil),it behaves like a bar magnet. One face of the coil acts as a North $(N)$ pole,while the opposite face acts as a South $(S)$ pole.
The polarity of the ends can be determined using the following rule:
$(1)$ If the current,when viewed from one end of the coil,appears to flow in a clockwise direction,that face behaves as a South $(S)$ pole.
$(2)$ If the current,when viewed from one end of the coil,appears to flow in an anticlockwise direction,that face behaves as a North $(N)$ pole.
This is illustrated in the provided figure,where the clockwise current corresponds to the South pole and the anticlockwise current corresponds to the North pole.

Explore More

Similar Questions

Two straight horizontal parallel wires are carrying the same current in the same direction, and $d$ is the distance between the wires. You are provided with a small freely suspended magnetic needle. At which of the following positions will the orientation of the needle be independent of the magnitude of the current in the wires?

In the Biot-Savart law,the direction of the magnetic field is determined by which of the following cross products in the expression $d\vec B = \frac{\mu_0}{4\pi} \frac{I d\vec l \times \vec r}{r^3}$?

$A$ length $L$ of wire carries a steady current $I$. It is bent first to form a circular plane coil of one turn. The same length is now bent more sharply to give a double loop of smaller radius. The magnetic field at the centre caused by the same current is

Two very thin metallic wires placed along $X$ and $Y$-axis carry equal currents as shown in the figure. $AB$ and $CD$ are lines at $45^\circ$ with the axes,with the origin of the axes at $O$. The magnetic field will be zero on the line:

$A$ current-carrying circular loop of radius '$R$' and a current-carrying long straight wire are placed in the same plane. The currents through the circular loop and the long straight wire are '$I_C$' and '$I_w$' respectively. The perpendicular distance between the centre of the circular loop and the wire is '$d$'. The magnetic field at the centre of the loop will be zero when the separation '$d$' is equal to:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo